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44 Challenging problems. Many are quite difficult, and tests if your physics understand is solid enough!
I've used FCKEditor and am looking to change to CKEditor 3.4.1. I was using the insertHtml plugin in fckeditor and was able to insert/embed widgets, google gadgets, iframes, html, etc all in one plugin. But the CKEditor plugin version of insertHtml does not work in version 3.4.1 and I hacked the plugin to insert/embed html, iframe and youtube code. But when I try to embed google gadgets or simple javascript it never gets ...
Hi,
is it possible to prevent the drag and drop functionality in the WYSIWYG area of CKEditor?
I am referring to this bug which is relevant only for Mozilla browsers so actually it is a Firefox bug but I need to prevent the drag and drop functionality anyway because the fix is to be expected at Firefox 3.6.11. ...
如何有效地融資，這是一家企業不時會面對的問題，較常用的融資方法有股本融資及借貸，那麼應該用股本融資還是借貸來籌集資金呢? 站在股東的角度，哪種方法比較有利呢?
This is a tutorial on arXiv about how negative refractive index emerges.
Vinay Deolalikar, HP Labs researcher, claimed to have proved NP not equal to P. The website is his homepage in HP. You can find his 103 paper in pdf here. And he said he will post the final version when ready. Here is his email claiming to have solved the problem:
I have a few problems with CKEditor.
It is very important for my users that a html source that is entered stays as entered and should not be "reformatted" by CKEditor. Means when a user enters (or pastes) a html source which consists of one single line (because of not producing to much spaces) it should also remain in one line. But when a user decides ...
In this paper, I will derive an explicit formula for the Euler zigzag numbers (Up/down numbers). Euler zigzag number is the number of alternating permutation in a set. Therefore the explicit formula of Euler numbers(Secant numbers) and Bernoulli numbers are found as well. The formula involves two finite sum.
I am going to solve a partial difference equation in this paper, which arises from binomial expansion of non-commutative matrix/operator.
In this paper, I am going to prove the identity:
e^(A+B) = e^(-lambda/2) e^A e^B
given [A, B] = lambda.
This formula is quite useful in quantum mechanics, and I will prove it using power series expansion ...
